merge-strings-alternately

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Algorithms

You are given two strings <code>word1</code> and <code>word2</code>. Merge the strings by adding letters in alternating order, starting with <code>word1</code>. If a string is longer than the other, append the additional letters onto the end of the merged string.

Return the merged string.

&nbsp;
Example 1:

<pre>
Input: word1 = &quot;abc&quot;, word2 = &quot;pqr&quot;
Output: &quot;apbqcr&quot;
Explanation:&nbsp;The merged string will be merged as so:
word1: a b c
word2: p q r
merged: a p b q c r
</pre>

Example 2:

<pre>
Input: word1 = &quot;ab&quot;, word2 = &quot;pqrs&quot;
Output: &quot;apbqrs&quot;
Explanation:&nbsp;Notice that as word2 is longer, &quot;rs&quot; is appended to the end.
word1: a b 
word2: p q r s
merged: a p b q r s
</pre>

Example 3:

<pre>
Input: word1 = &quot;abcd&quot;, word2 = &quot;pq&quot;
Output: &quot;apbqcd&quot;
Explanation:&nbsp;Notice that as word1 is longer, &quot;cd&quot; is appended to the end.
word1: a b c d
word2: p q 
merged: a p b q c d
</pre>

&nbsp;
Constraints:

<ul>
	<li><code>1 &lt;= word1.length, word2.length &lt;= 100</code></li>
	<li><code>word1</code> and <code>word2</code> consist of lowercase English letters.</li>
</ul>

第 229 场周赛

weekly-contest-229

mergeAlternately

Merge Strings Alternately

Zigzag Iterator

zigzag-iterator

锯齿迭代器

Minimum Additions to Make Valid String

minimum-additions-to-make-valid-string

构造有效字符串的最少插入数

Two Pointers

String

给你两个字符串 <code>word1</code> 和 <code>word2</code> 。请你从 <code>word1</code> 开始，通过交替添加字母来合并字符串。如果一个字符串比另一个字符串长，就将多出来的字母追加到合并后字符串的末尾。

返回 合并后的字符串 。

 

示例 1：

<pre>
输入：word1 = "abc", word2 = "pqr"
输出："apbqcr"
解释：字符串合并情况如下所示：
word1： a b c
word2： p q r
合并后： a p b q c r
</pre>

示例 2：

<pre>
输入：word1 = "ab", word2 = "pqrs"
输出："apbqrs"
解释：注意，word2 比 word1 长，"rs" 需要追加到合并后字符串的末尾。
word1： a b 
word2： p q r s
合并后： a p b q r s
</pre>

示例 3：

<pre>
输入：word1 = "abcd", word2 = "pq"
输出："apbqcd"
解释：注意，word1 比 word2 长，"cd" 需要追加到合并后字符串的末尾。
word1： a b c d
word2： p q 
合并后： a p b q c d
</pre>

 

提示：

<ul>
	<li><code>1 <= word1.length, word2.length <= 100</code></li>
	<li><code>word1</code> 和 <code>word2</code> 由小写英文字母组成</li>
</ul>