construct-binary-search-tree-from-preorder-traversal

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Algorithms

Given an array of integers preorder, which represents the preorder traversal of a BST (i.e., binary search tree), construct the tree and return its root.

It is guaranteed that there is always possible to find a binary search tree with the given requirements for the given test cases.

A binary search tree is a binary tree where for every node, any descendant of <code>Node.left</code> has a value strictly less than <code>Node.val</code>, and any descendant of <code>Node.right</code> has a value strictly greater than <code>Node.val</code>.

A preorder traversal of a binary tree displays the value of the node first, then traverses <code>Node.left</code>, then traverses <code>Node.right</code>.

&nbsp;
Example 1:
<img alt="" src="https://assets.leetcode.com/uploads/2019/03/06/1266.png" style="height: 386px; width: 590px;" />
<pre>
Input: preorder = [8,5,1,7,10,12]
Output: [8,5,10,1,7,null,12]
</pre>

Example 2:

<pre>
Input: preorder = [1,3]
Output: [1,null,3]
</pre>

&nbsp;
Constraints:

<ul>
	<li><code>1 &lt;= preorder.length &lt;= 100</code></li>
	<li><code>1 &lt;= preorder[i] &lt;= 1000</code></li>
	<li>All the values of <code>preorder</code> are unique.</li>
</ul>

第 127 场周赛

weekly-contest-127

bstFromPreorder

Construct Binary Search Tree from Preorder Traversal

Stack

Tree

Binary Search Tree

Array

Binary Tree

Monotonic Stack

给定一个整数数组，它表示BST(即 二叉搜索树 )的 先序遍历 ，构造树并返回其根。

保证 对于给定的测试用例，总是有可能找到具有给定需求的二叉搜索树。

二叉搜索树 是一棵二叉树，其中每个节点，&nbsp;<code>Node.left</code>&nbsp;的任何后代的值 严格小于 <code>Node.val</code>&nbsp;,&nbsp;<code>Node.right</code>&nbsp;的任何后代的值 严格大于 <code>Node.val</code>。

二叉树的 前序遍历 首先显示节点的值，然后遍历<code>Node.left</code>，最后遍历<code>Node.right</code>。

&nbsp;

示例 1：

<img src="https://assets.leetcode.com/uploads/2019/03/06/1266.png" />

<pre>
输入：preorder = [8,5,1,7,10,12]
输出：[8,5,10,1,7,null,12]
</pre>

示例 2:

<pre>
输入: preorder = [1,3]
输出: [1,null,3]
</pre>

&nbsp;

提示：

<ul>
	<li><code>1 &lt;= preorder.length &lt;= 100</code></li>
	<li><code>1 &lt;= preorder[i]&nbsp;&lt;= 10^8</code></li>
	<li><code>preorder</code> 中的值 互不相同</li>
</ul>

&nbsp;