actors-and-directors-who-cooperated-at-least-three-times

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Database

Table: <code>ActorDirector</code>

<pre>
+-------------+---------+
| Column Name | Type |
+-------------+---------+
| actor_id | int |
| director_id | int |
| timestamp | int |
+-------------+---------+
timestamp is the primary key (column with unique values) for this table.
</pre>

&nbsp;

Write a solution to find all the pairs <code>(actor_id, director_id)</code> where the actor has cooperated with the director at least three times.

Return the result table in any order.

The result format is in the following example.

&nbsp;
Example 1:

<pre>
Input: 
ActorDirector table:
+-------------+-------------+-------------+
| actor_id | director_id | timestamp |
+-------------+-------------+-------------+
| 1 | 1 | 0 |
| 1 | 1 | 1 |
| 1 | 1 | 2 |
| 1 | 2 | 3 |
| 1 | 2 | 4 |
| 2 | 1 | 5 |
| 2 | 1 | 6 |
+-------------+-------------+-------------+
Output: 
+-------------+-------------+
| actor_id | director_id |
+-------------+-------------+
| 1 | 1 |
+-------------+-------------+
Explanation: The only pair is (1, 1) where they cooperated exactly 3 times.
</pre>

actors_and_directors

Actors and Directors Who Cooperated At Least Three Times

<code>ActorDirector</code>&nbsp;表：

<pre>
+-------------+---------+
| Column Name | Type |
+-------------+---------+
| actor_id | int |
| director_id | int |
| timestamp | int |
+-------------+---------+
timestamp 是这张表的主键(具有唯一值的列).
</pre>

&nbsp;

编写解决方案找出合作过至少三次的演员和导演的 id 对&nbsp;<code>(actor_id, director_id)</code>

&nbsp;

示例 1：

<pre>
输入：
ActorDirector 表：
+-------------+-------------+-------------+
| actor_id | director_id | timestamp |
+-------------+-------------+-------------+
| 1 | 1 | 0 |
| 1 | 1 | 1 |
| 1 | 1 | 2 |
| 1 | 2 | 3 |
| 1 | 2 | 4 |
| 2 | 1 | 5 |
| 2 | 1 | 6 |
+-------------+-------------+-------------+
输出：
+-------------+-------------+
| actor_id | director_id |
+-------------+-------------+
| 1 | 1 |
+-------------+-------------+
解释：
唯一的 id 对是 (1, 1)，他们恰好合作了 3 次。</pre>